对于(3)式中假定的一类局域量子态
ρBC =
ρB $\otimes$
ρC ,即其中
ρB 是非简并且有谱投影{|
eB ><
eB |},而
ρC 是简并的情况,文献[
32 ]给出了态
ρAB $\otimes$
ρCD 测量诱导的非双局域关联上界。接下来,应用文献[
20 ]中的方法对这类态的上界进行优化。
由于(3)式中只需要对tr(TCD T T C D )- m i n C tr(CTCD T T C D C T )进行上界的计算,下面研究边缘态ρC 有d 个维度为ur 的简并子空间情况下量子态非双局域关联的计算问题。
(4) ρCD = ∑ k = 1 u 2 ∑ l = 0 v 2 - 1 ckl Z'k $\otimes$Wl 。
式中:集合{Wl }与(2)式中所用的集合一样;集合{Z'k }是由ρC 的特征向量所构造。给出ρC 的谱分解ρC = ∑ r = 1 d er ∑ s = 1 u r |xrs ><xrs |+ ∑ r = 1 d ' e'r |xr ><xr |,其中{er :r =1,2,…,d }({e'r :r =1,2,…,d' })是ρC 的简并(非简并)特征值。在这个关系中,假定ρC 有d +d' (1≤d +d' ≤u )个不同的特征值,且每个特征值er 被重复了ur 次(2≤ur ≤u ,d' + ∑ r = 1 d ur =u )。同样,ρC 的简并特征向量被表示为|xrs >,其中第一个指标确定了相应的特征值,第二个指标与指标“r ”指定的特征值的简并度有关。ρC 的非简并特征向量被表示为|xr >。
首先,集合{|xrs >}是不唯一的,同一特征向量|xrs >的任意线性组合仍然是ρC 的一个特征向量。为了对集合{Z'k }进行构造,本文选择了其中一个集合,并表示为{|x'rs >}。用{|x'rs ><x'rs |:s ,s' =1,2,…,ur }的线性组合构造算子{Z'k :k =Br -1 +2,Br -1 +1,…,Br },其中Br = u 1 2 + u 2 2 ,…+ u r 2 ,B 0 =0,且设
Z ' 1 + B r - 1 = 1 u r ∑ s = 1 u r |x'rs ><x'rs |,
这样就形成了一组满足条件tr(Z'k Z'k' )=δkk' 的厄米算子集合。进而令{Z ' B d + r =|xr ><xr |},并用|x'rs ><xr' |和|x'rs ><x'r's' |(r ≠r' )的线性组合构造集合{Z'k :k =D ,…,u 2 }(Bd +d' +1=D ),且满足条件Z'k = Z k ' † ,tr(Z'k Z'k' )=δkk' , tr(|x'rs ><x'rs |Z'k )=0和tr(|xr ><xr |Z'k )=0。
用ρC 在新基下的展开来计算tr(TCD T T C D )- m i n C tr(CTCD T T C D C T )= m a x Π C ‖ρCD -ΠC (ρCD )‖2 的上界。如前所述,等式(3)中所用的ΠC ={ Π f C }一定是ρC 的一个谱投影,即
ΠC ={ Π f C }={ Π x r s C =|xrs ><xrs |}+
在施加保持ρC 不变的冯诺依曼测量ΠC 之后,态ρCD 变为
ΠC (ρCD )= ∑ r = 1 d ∑ s = 1 u r ( Π x r s C $\otimes$ID )ρCD ( Π x r s C $\otimes$ID )+ ∑ r = 1 d ' ( Π x r C $\otimes$ID )ρCD ( Π x r C $\otimes$ID )。
ΠC (ρCD )= ∑ r = 1 d ∑ s = 1 u r ∑ k = 1 u 2 ∑ l = 0 v 2 - 1 ckl Π x r s C Z'k Π x r s C $\otimes$Wt +
∑ r = 1 d ' ∑ k = 1 u 2 ∑ l = 0 v 2 - 1 ckl Π k r C Z'k Π k r C $\otimes$Wl 。
由上述对于{Z'k }的构造可得,{ Π x r s C Z'k Π x r s C =0:k ≠Fr ,…,Br }和{ Π x r C Z'k Π x r C =0:k ≠Bd +1,…,Bd +d' },其中Fr =Br -1 +1。于是有
ΠC (ρCD )= ∑ r = 1 d ∑ s = 1 u r ∑ k = F r B r ∑ l = 0 v 2 - 1 ckl Π x r s C Z'k Π x r s C $\otimes$Wl + ∑ k = B d + 1 B d + d ' ∑ l = 0 v 2 - 1 ckl Z'k $\otimes$Wl ,
ρCD -ΠC (ρCD )= ∑ r = 1 d ∑ k = F r B r ∑ l = 0 v 2 - 1 ckl (Z'k -
∑ s = 1 u r Π x r s C Z'k Π x r s C )Wl +
∑ k = D u 2 ∑ l = 0 v 2 - 1 ckl Z'k $\otimes$Wl 。
另一方面由等式(4)和在冯诺依曼测量下ρC 的不变性可知
ρC = ∑ k = 1 u 2 c k 0 Z'k v ,
ρC = ∑ r = 1 d ∑ s = 1 u r Π x r s C ρC Π x r s C + ∑ r = 1 d ' Π x r C ρC Π x r C ,
∑ k = 1 u 2 c k 0 Z'k = ∑ r = 1 d ∑ s = 1 u r ∑ k = F r B r c k 0 Π x r s C Z'k Π x r s C +
∑ k = B d + 1 B d + d c k 0 Z'k ,
∑ r = 1 d ∑ k = F r B d c k 0 (Z'k - ∑ s = 1 u r Π x r s C Z'k Π x r s C )+ ∑ k = D u 2 c k 0 Z'k =0。
所以对于前面计算的ρCD -ΠC (ρCD ),l =0时的项为0。若定义Xrsk ≡tr Π x r s C Z'k ,则
(5) $\begin{array}{c}\left\|\rho_{C D}-\Pi^{C}\left(\rho_{C D}\right)\right\|^{2}=\sum_{l=1}^{v^{2}-1}\left(\sum_{k=D}^{u^{2}} c_{k l}^{2}+\right. \\\left.\sum_{r=1}^{d} \sum_{k=F_{r}}^{B_{r}}\left(c_{k l}^{2}-\sum_{k^{\prime}=F_{r}}^{B_{r}} \sum_{s=1}^{u_{r}} X_{r s k} X_{r s k^{\prime}} c_{k l} c_{k^{\prime} l}\right)\right)\end{array}$
由{Z'k }的构造可知 X r s F r =1/ u r ,而对于不扰动局域态的冯诺依曼测量ΠC ={ Π f C }={ Π x r s C =|xrs ><xrs |}+{ Π x r C =|xr ><xr |}来说,它必须满足2个条件:① Π f C Π f ' C =δff' Π f C ;② ∑ f = 1 u Π f C =IC 。对于条件①,
Π f C Π f ' C =δff' Π f C ⇒ ∑ k , k ' = 0 u 2 - 1 cfk cf'k' Zk Zk' =δff' ∑ k = 0 u 2 - 1 cfk Zk ⇒
∑ k , k ' = F r B r Xrsk Xrs'k' Zk Zk' =δss' ∑ k = F r B r Xrsk Zk ;
对于条件②,由于 X r s F r =1/ u r ,故
∑ f = 1 u Π f C =IC ⇒ ∑ f = 1 u cfk =0(k =1,2,…,u 2 -1)⇒
∑ s = 1 u r Xrsk =0(k =Br -1 +2,…,Br )。
所以,等式(5)中k =Fr 或k' =Fr 时的项为0,且可最终写为
(6) $\begin{array}{r}\left\|\rho_{C D}-\Pi^{C}\left(\rho_{C D}\right)\right\|=\sum_{k=D}^{u_{2}} \sum_{l=1}^{v^{2}-1} c_{k l}^{2}+ \\\sum_{r=1}^{d}\left(\operatorname{tr}\left(\boldsymbol{C}_{r} \boldsymbol{C}_{r}^{\mathrm{T}}\right)-\operatorname{tr} \mathbf{X}_{r} \boldsymbol{C}_{r} \boldsymbol{C}_{r}^{\mathrm{T}} \boldsymbol{X}_{r}^{\mathrm{T}}\right),\end{array}$
式中:Cr 是一个( u r 2 -1)×(v 2 -1)维矩阵,其元素为{ckl :k =Br -1 +2,…,Br };Xr 是一个ur ×( u r 2 -1)维矩阵,其元素为{Xrsk :s =1,2,…,ur :k =Br -1 +2,…,Br }。经计算可得,
(7) $\begin{array}{c}\operatorname{tr}\left(\boldsymbol{T}_{C D} \boldsymbol{T}_{C D}^{\mathrm{T}}\right)-\min _{C} \operatorname{tr}\left(\boldsymbol{C}_{C D} \boldsymbol{T}_{C D}^{\mathrm{T}} \boldsymbol{C}^{\mathrm{T}}\right)= \\\max _{I^{C}}\left\|\rho_{C D}-\Pi^{C}\left(\rho_{C D}\right)\right\|^{2}= \\\sum_{k=D}^{u^{2}} \sum_{l=1}^{v^{2}-1} c_{k l}^{2}+\sum_{r=1}^{d} \max \left(\operatorname{tr}\left(\boldsymbol{C}_{r} \boldsymbol{C}_{r}^{\mathrm{T}}\right)-\right. \\\left.\operatorname{tr}\left(\boldsymbol{X}_{r} \boldsymbol{C}_{r} \boldsymbol{C}_{r}^{\mathrm{T}} \boldsymbol{X}_{r}^{\mathrm{T}}\right)\right)= \\\sum_{k=D}^{u^{2}} \sum_{l=1}^{v^{2}-1} c_{k l}^{2}+\sum_{r=1}^{d}\left(\operatorname{tr}\left(\boldsymbol{C}_{r} \boldsymbol{C}_{r}^{\mathrm{T}}\right)-\right. \\\left.\min _{k_{r}} \operatorname{tr}\left(\boldsymbol{X}_{r} \boldsymbol{C}_{r} \boldsymbol{C}_{r}^{\mathrm{T}} \boldsymbol{X}_{r}^{\mathrm{T}}\right)\right) 。\end{array}$
根据文献[
32 ],可从等式(7)中得出一个上界,即
(8) $\begin{array}{c}\operatorname{tr}\left(\boldsymbol{T}_{C D} \boldsymbol{T}_{C D}^{\mathrm{T}}\right)-\min _{C} \operatorname{tr}\left(\boldsymbol{C} \boldsymbol{T}_{C D} \boldsymbol{T}_{C D}^{\mathrm{T}} \boldsymbol{C}^{\mathrm{T}}\right) \leqslant \\\sum_{r=1}^{d} \sum_{k=1}^{u_{r}^{2}-u_{r}} \lambda_{r k}+\sum_{k=D}^{u^{2}} \sum_{l=1}^{v^{2}-1} c_{k l}^{2},\end{array}$
式中{λrk :k =1,2,…, u r 2 -1}是矩阵Cr C T r 按降序排列的特征值。
(9) $\begin{array}{l}N_{C}\left(\rho_{A B} \otimes \rho_{C D}\right)= \\\left(\operatorname{tr}\left(\boldsymbol{T}_{A B} \boldsymbol{T}_{A B}^{\mathrm{T}}\right)-\operatorname{tr}\left(\boldsymbol{B} \boldsymbol{T}_{A B}^{\mathrm{T}} \boldsymbol{T}_{A B} \boldsymbol{B}^{\mathrm{T}}\right)\right)\left(\frac{1}{u v}+\right. \\\left.\|\boldsymbol{z}\|^{2}+\|\boldsymbol{w}\|^{2}+\operatorname{tr}\left(\boldsymbol{T}_{C D} \boldsymbol{T}_{C D}^{\mathrm{T}}\right)\right)+ \\\left(\frac{1}{m n}+\|\boldsymbol{x}\|^{2}+\|\boldsymbol{y}\|^{2}+\right. \\\left.\operatorname{tr}\left(\boldsymbol{B} \boldsymbol{T}_{A B}^{\mathrm{T}} \boldsymbol{T}_{A B} \boldsymbol{B}^{\mathrm{T}}\right)\right)\left(\sum_{k=D}^{u^{2}} \sum_{l=1}^{v^{2}-1} c_{k l}^{2}+\right. \\\left.\sum_{r=1}^{d}\left(\operatorname{tr}\left(\boldsymbol{C}_{r} \boldsymbol{C}_{r}^{\mathrm{T}}\right)-\min _{K_{r}} \operatorname{tr}\left(\boldsymbol{X}_{r} \boldsymbol{C}_{r} \boldsymbol{C}_{r}^{\mathrm{T}} \boldsymbol{X}_{r}^{\mathrm{T}}\right)\right)\right) \leqslant \\\left(\operatorname{tr}\left(\boldsymbol{T}_{A B} \boldsymbol{T}_{A B}^{\mathrm{T}}\right)-\operatorname{tr}\left(\boldsymbol{B} \boldsymbol{T}_{A B}^{\mathrm{T}} \boldsymbol{T}_{A B} \boldsymbol{B}^{\mathrm{T}}\right)\right)\left(\frac{1}{u v}+\right. \\\left.\|\boldsymbol{z}\|^{2}+\|\boldsymbol{w}\|^{2}+\operatorname{tr}\left(\boldsymbol{T}_{C D} \boldsymbol{T}_{C D}^{\mathrm{T}}\right)\right)+\left(\frac{1}{m n}+\right. \\\left.\|\boldsymbol{x}\|^{2}+\|\boldsymbol{y}\|^{2}+\operatorname{tr}\left(\boldsymbol{B} \boldsymbol{T}_{A B}^{\mathrm{T}} \boldsymbol{T}_{A B} \boldsymbol{B}^{\mathrm{T}}\right)\right) \cdot \\\left(\sum_{r=1}^{d} \sum_{k=1}^{u_{r}^{2}-u_{r}} \lambda_{r k}+\sum_{k=D}^{u^{2}} \sum_{l=1}^{v^{2}-1} c_{k l}^{2}\right) 。 \\\end{array}$
由于这个上界可在每个简并特征子空间下独立计算得出,所以减少了以前上界(在整个空间下计算)的计算量,优化了最终的结果。